Calc Stress in Steel Beam: F=10kN, A=100mm^2

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SUMMARY

The discussion centers on calculating the stress in a steel beam with a quadratic cross-section, given a force of 10 kN and an area of 100 mm². The calculated stress is 100 MPa, derived from the formula σ = F/A. Participants clarify that the yield strength of steel is not provided, and the stress must be compared against known yield strength values to ensure it does not exceed them. The importance of unit consistency is emphasized, particularly the equivalence of MPa to N/mm².

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  • Understanding of basic mechanics and stress calculations
  • Familiarity with units of measurement in engineering (MPa, N/mm²)
  • Knowledge of yield strength concepts in materials science
  • Ability to interpret Failure Assessment Diagrams (FAD)
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  • Research the yield strength of common steel grades
  • Learn about Failure Assessment Diagrams (FAD) and their applications
  • Explore advanced stress analysis techniques for structural engineering
  • Study the implications of unit conversions in engineering calculations
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Students in mechanical or civil engineering, structural engineers, and professionals involved in material strength assessments will benefit from this discussion.

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Homework Statement



[PLAIN]http://img17.imageshack.us/img17/5112/ph2b.jpg a) This steel beam has a quadratic cross-section (A=100mm2). The force F is 10 kN. Calculate the stress in the rod and show that this stress does not exceed the yield strength of the steel.[PLAIN]http://img600.imageshack.us/img600/1163/phya.jpg 2. The attempt at a solution

a)

\sigma = \frac{10000N}{0.0001m^2}=100 MPa

I guess this is right? I'm not sure what the yield strength is. Can I calculate it from the given formulas?
 
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The result is okay, but note that [MPa] = [N/mm^2], and not [N/m^2], i.e. you didn't need to convert A into [m^2]. I'm not sure what the expressions in the image mean - are you given a yield strength for steel?
 
Thanks for replying.

No, nothing else is given. It is a so-called Failure Assessment Diagram (FAD).
 

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