Simple framework, maximum force and stress.

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SUMMARY

The discussion centers on calculating the maximum force and stress in a simple framework consisting of two steel rods (30x30 mm cross-section, material grade 1550-01, Young's modulus E = 210 GPa) linked at points A, B, and C. The maximum force F was determined to be 22.4 kN using the formula Fb = π² * E * I / L², where I is the moment of inertia calculated as I = w * h² / 12. The stress in rod BC was calculated to be 24.9 MPa using the formula σ = F/A, where A is the cross-sectional area. The user seeks confirmation on these calculations and guidance on determining the stress in rod AB.

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Homework Statement


A simple framework by two rods linked in A, B and C. Burdened by a force F. The rods is of square cross section 30x30 mm and made by steel 1550-01 -> E = 210 GPa.


[PLAIN]http://img718.imageshack.us/img718/125/ram001.jpg

Determinate maximum force F and the stress in the rods AB and BC.

Homework Equations


I = w*h^2/12

Fb = pi^2*E*I/L^2


The Attempt at a Solution


My guess is that It's enough to calculate the breaking of BC to get the maximum force F.

I = 0,03^4/12 = 6,75*10^-8 m^2

Fb = 22,4 kN

Then I assumed I could use tanX = a/b -> (a=F) -> F = 22,4*tan30 = 12,932 kN.

Could that be the correct answer?


For the stress I guess I should use σ=F/A, just by putting the things I got into that I get 22400/9*10^4 = 24,9 MPa, could that be the stress in BC? But then how do I get the stress in AB?
 
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Anyone got an idea for this?
 

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