Calc Volumes of Rotation Bodies | x-axis & 7x-x^2

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Discussion Overview

The discussion revolves around calculating the volumes of rotation bodies formed by the area bounded by the x-axis and the curve $$7x-x^2$$ when rotated about the x-axis and y-axis. Participants explore the application of different volume formulas and methods in calculus.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant presents calculations for volumes of rotation using both the shell method for rotation about the y-axis and the disk method for rotation about the x-axis.
  • Another participant questions the initial claim of something being wrong, suggesting that the expectation of equal volumes for different axes of rotation may be incorrect for this specific curve.
  • It is noted that the formula for the shell method provided by the first participant is missing the radius of the shell, which is essential for correct volume calculation.
  • A later reply confirms the need to express the radius in terms of x and suggests a corrected formula for the shell method.
  • The original poster acknowledges the mistake and provides a revised formula, which they state yields the correct answer.

Areas of Agreement / Disagreement

Participants generally agree on the need for correct application of formulas, but there is no consensus on the initial calculations presented by the first participant until corrections are made.

Contextual Notes

Some assumptions regarding the formulas used and the specific characteristics of the curve may not be fully explored, leading to potential misunderstandings in volume calculations.

Petrus
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Calculate the volumes of the rotation bodies which arises when the area D in the xy-plane bounded by x-axis and curve $$7x-x^2$$may rotate around x- respective y-axes.
I will calculate $$V_x$$ and $$V_y$$ I start to get crit point $$x_1=0$$ and $$x_2=7$$
rotate on y-axe:
$$2\pi\int_a^bf(x)dx$$
so we get $$2\pi[\frac{7x^2}{2}-\frac{x^3}{3}]_0^7$$ $$V_y=\frac{2\pi*343}{6}$$
rotate on x axe:
$$\pi\int_a^bf(x)^2dx$$
so we start with:$$(7x-x^2)^2=49x^2-14x^3+x^4$$ so we get $$[\frac{49x^3}{3}-\frac{14x^4}{4}+\frac{x^5}{5}]_0^7$$ that means $$V_x=\frac{16087\pi}{30}$$ What I am doing wrong?

(Sorry for bad english.)
 
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First , why do you think you are doing something wrong ?
 
I was going to ask the same thing...are you expecting you should get the same volume with a different axis of rotation? This in only true with the axes you are given for a particular family of parabolas, and this one is not in that family. See this topic:

http://www.mathhelpboards.com/f35/problem-week-37-december-10th-2012-a-2714/

I believe that problem was inspired by a problem I helped you with in the past. :cool:

Your formula for the shell method (revolving about the $y$-axis) is missing the radius of the shell. Your other formula for the disk method (revolving about the $x$-axis) is correct.
 
MarkFL said:
I was going to ask the same thing...are you expecting you should get the same volume with a different axis of rotation? This in only true with the axes you are given for a particular family of parabolas, and this one is not in that family. See this topic:

http://www.mathhelpboards.com/f35/problem-week-37-december-10th-2012-a-2714/

I believe that problem was inspired by a problem I helped you with in the past. :cool:

Your formula for the shell method (revolving about the $y$-axis) is missing the radius of the shell. Your other formula for the disk method (revolving about the $x$-axis) is correct.
Well its a programe we put our answer on so we see if we get correct or wrong:P what do you mean missing the radius of the shell?
 
Petrus said:
...what do you mean missing the radius of the shell?

The volume of an arbitrary shell is:

$$dV=2\pi rh\,dx$$

where:

$$h=f(x)$$

You also need to write $r$ in terms of $x$. Do you see how your formula is missing the radius?
 
MarkFL said:
The volume of an arbitrary shell is:

$$dV=2\pi rh\,dx$$

where:

$$h=f(x)$$

You also need to write $r$ in terms of $x$. Do you see how your formula is missing the radius?
Yes I do, I did think wrong when I try use my brain(and some memory) for the formula. $$2\pi\int_0^7x(7x-x^2)$$ is this correct now?Edit: got correct answer! Thanks MarkFL and ZaidAylafey!:)
 
Last edited:

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