MHB Calc Volumes of Rotation Bodies | x-axis & 7x-x^2

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The discussion focuses on calculating the volumes of rotation for the area bounded by the x-axis and the curve 7x - x^2, specifically when rotated around the x-axis and y-axis. The initial calculations for volume using the shell method and disk method were incorrect due to a missing radius in the shell method formula. After clarification, the correct formula was applied, leading to the correct volume calculation for the rotation around the y-axis. The participant successfully revised their approach and confirmed they received the correct answer afterward. The thread emphasizes the importance of proper formula application in volume calculations.
Petrus
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Calculate the volumes of the rotation bodies which arises when the area D in the xy-plane bounded by x-axis and curve $$7x-x^2$$may rotate around x- respective y-axes.
I will calculate $$V_x$$ and $$V_y$$ I start to get crit point $$x_1=0$$ and $$x_2=7$$
rotate on y-axe:
$$2\pi\int_a^bf(x)dx$$
so we get $$2\pi[\frac{7x^2}{2}-\frac{x^3}{3}]_0^7$$ $$V_y=\frac{2\pi*343}{6}$$
rotate on x axe:
$$\pi\int_a^bf(x)^2dx$$
so we start with:$$(7x-x^2)^2=49x^2-14x^3+x^4$$ so we get $$[\frac{49x^3}{3}-\frac{14x^4}{4}+\frac{x^5}{5}]_0^7$$ that means $$V_x=\frac{16087\pi}{30}$$ What I am doing wrong?

(Sorry for bad english.)
 
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First , why do you think you are doing something wrong ?
 
I was going to ask the same thing...are you expecting you should get the same volume with a different axis of rotation? This in only true with the axes you are given for a particular family of parabolas, and this one is not in that family. See this topic:

http://www.mathhelpboards.com/f35/problem-week-37-december-10th-2012-a-2714/

I believe that problem was inspired by a problem I helped you with in the past. :cool:

Your formula for the shell method (revolving about the $y$-axis) is missing the radius of the shell. Your other formula for the disk method (revolving about the $x$-axis) is correct.
 
MarkFL said:
I was going to ask the same thing...are you expecting you should get the same volume with a different axis of rotation? This in only true with the axes you are given for a particular family of parabolas, and this one is not in that family. See this topic:

http://www.mathhelpboards.com/f35/problem-week-37-december-10th-2012-a-2714/

I believe that problem was inspired by a problem I helped you with in the past. :cool:

Your formula for the shell method (revolving about the $y$-axis) is missing the radius of the shell. Your other formula for the disk method (revolving about the $x$-axis) is correct.
Well its a programe we put our answer on so we see if we get correct or wrong:P what do you mean missing the radius of the shell?
 
Petrus said:
...what do you mean missing the radius of the shell?

The volume of an arbitrary shell is:

$$dV=2\pi rh\,dx$$

where:

$$h=f(x)$$

You also need to write $r$ in terms of $x$. Do you see how your formula is missing the radius?
 
MarkFL said:
The volume of an arbitrary shell is:

$$dV=2\pi rh\,dx$$

where:

$$h=f(x)$$

You also need to write $r$ in terms of $x$. Do you see how your formula is missing the radius?
Yes I do, I did think wrong when I try use my brain(and some memory) for the formula. $$2\pi\int_0^7x(7x-x^2)$$ is this correct now?Edit: got correct answer! Thanks MarkFL and ZaidAylafey!:)
 
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