Calcium current to amount of substance units (mol)

  • Level: Graduate 
  • Thread starter Thread starter gjfelix2001
  • Start date Start date
  • Tags Tags
    Calcium Current Units
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
gjfelix2001
Messages
17
Reaction score
0
Hi there... I have a differential equation with to terms:

[tex]\frac{d[Ca2+]}{dt}=f\Big(\frac{3I_{Ca}}{z 4 \pi r^3 F}-k_{Ca}[Ca2+]\Big)[/tex]


I think that the first term converts the Ca2+ (density of?) current to mol units. But, where does it comes from?

[tex]z[/tex] is the valence; in this case of the Ca2+, [tex]r[/tex] is the radius of a cell, [tex]F[/tex] is the Faraday's constant, and [tex]I_{Ca}[/tex] is a Ca2+ current, or may be density of current. [tex]k_{Ca}[/tex] is a rate with [tex]ms^{-1}[/tex] units, and [tex][Ca2+][/tex] is a concentration with mol units... In this case, r is the radius of a cell...

Thanks a lot...
 
Physics news on Phys.org
Any context to that question? It is even hard to start thinking over some equation coming out of a blue.