Calculate Absolute Pressure with P = pgh

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To calculate absolute pressure using the formula P = pgh, it's essential to understand how to convert measurements, such as 750 mm of Hg, into pressure. The discussion emphasizes that starting from a known pressure, typically atmospheric pressure, you add pressure when moving down and subtract when moving up. There is some confusion regarding the directionality of these calculations, but the consensus is that the method involves adding pressure when descending and subtracting when ascending. Clarification on the density of mercury is also noted as necessary for accurate calculations. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement


the question is in the diagram i have attached. basically i have to find absolute pressure

Homework Equations


P = pgh where P is Pressure and p is density


The Attempt at a Solution



1st of all i need to convert 750mm into a pressure? somehow don't know exactly.

the rule i was told is starting from the right side, if it goes down it is subtracted and if it goes up it is added. So in knowing that i did: p_atm - (8 * 0.15 ) - ( 10* 0.05) but i don't know the pressure yet coz i don't know how to calculate. is the rest of the method correct though?
 

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Hi TyErd! :smile:
TyErd said:
1st of all i need to convert 750mm into a pressure? somehow don't know exactly.

(you mean 758 :wink:)

758 mm of Hg means the pressure at the bottom of a tube of Hg 758mm high …

so you need to know the density of Hg. :smile:
the rule i was told is starting from the right side, if it goes down it is subtracted and if it goes up it is added. So in knowing that i did: p_atm - (8 * 0.15 ) - ( 10* 0.05) but i don't know the pressure yet coz i don't know how to calculate. is the rest of the method correct though?

Isn't it adding for both of them?

You start with atmospheric https://www.physicsforums.com/library.php?do=view_item&itemid=80" and then it increases when you go down …

don't you have to go down from the interface to that little arrow? :redface:
 
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okay i get how to calculate the atmospheric pressure now. According to my book and a couple of questions completed with a teacher, If you are starting from the left, you add as you down and subtract as it goes up. And I think he said if you start from the right side, its add if you up and subtract if you go down. I'm not too sure, I need someone to confirm it that's right or not.
 
Hi TyErd! :smile:

Forget left and right.

You start with a place where you already know the pressure (usually because it's atmospheric pressure), then if you go down the pressure goes up (ie you add), and if you go up the pressure goes down (ie you subtract). :wink:
 
thanks so much! makes a lot more sense now. you're the man
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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