Calculate Absolute Pressure with P = pgh

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Homework Help Overview

The discussion revolves around calculating absolute pressure using the formula P = pgh, where P represents pressure and p denotes density. The original poster seeks to understand how to convert a height measurement (750 mm) into a pressure value and how to apply the pressure calculation method correctly in the context of a diagram provided.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the conversion of height in mm to pressure, questioning the correct method for applying atmospheric pressure in calculations. There is discussion about whether to add or subtract pressure based on the direction of measurement in the diagram.

Discussion Status

Participants are actively engaging with the problem, with some providing clarifications on how to approach the calculation of pressure. There is a recognition of differing interpretations regarding the addition and subtraction of pressure based on the direction of measurement, indicating a productive exploration of the topic.

Contextual Notes

There is mention of a diagram that is referenced but not visible in the discussion, which may contain critical information for solving the problem. Additionally, participants are discussing the density of mercury as a necessary component for the calculations, suggesting that further information may be needed to proceed accurately.

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Homework Statement


the question is in the diagram i have attached. basically i have to find absolute pressure

Homework Equations


P = pgh where P is Pressure and p is density


The Attempt at a Solution



1st of all i need to convert 750mm into a pressure? somehow don't know exactly.

the rule i was told is starting from the right side, if it goes down it is subtracted and if it goes up it is added. So in knowing that i did: p_atm - (8 * 0.15 ) - ( 10* 0.05) but i don't know the pressure yet coz i don't know how to calculate. is the rest of the method correct though?
 

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Hi TyErd! :smile:
TyErd said:
1st of all i need to convert 750mm into a pressure? somehow don't know exactly.

(you mean 758 :wink:)

758 mm of Hg means the pressure at the bottom of a tube of Hg 758mm high …

so you need to know the density of Hg. :smile:
the rule i was told is starting from the right side, if it goes down it is subtracted and if it goes up it is added. So in knowing that i did: p_atm - (8 * 0.15 ) - ( 10* 0.05) but i don't know the pressure yet coz i don't know how to calculate. is the rest of the method correct though?

Isn't it adding for both of them?

You start with atmospheric https://www.physicsforums.com/library.php?do=view_item&itemid=80" and then it increases when you go down …

don't you have to go down from the interface to that little arrow? :redface:
 
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okay i get how to calculate the atmospheric pressure now. According to my book and a couple of questions completed with a teacher, If you are starting from the left, you add as you down and subtract as it goes up. And I think he said if you start from the right side, its add if you up and subtract if you go down. I'm not too sure, I need someone to confirm it that's right or not.
 
Hi TyErd! :smile:

Forget left and right.

You start with a place where you already know the pressure (usually because it's atmospheric pressure), then if you go down the pressure goes up (ie you add), and if you go up the pressure goes down (ie you subtract). :wink:
 
thanks so much! makes a lot more sense now. you're the man
 

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