Calculate Current Drawing at 120V After 15.8% Voltage Reduction

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SUMMARY

The discussion focuses on calculating the current drawn by an electrical device at 120V after a 15.8% voltage reduction. Initially, the device draws 2.56 A at 120 V with a resistance of 46.875 ohms. The correct approach involves adjusting the resistance to 85% of its original value, leading to a new resistance of 39.375 ohms. The current can then be accurately calculated using Ohm's Law, resulting in a current of approximately 3.05 A.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Basic knowledge of electrical resistance and current
  • Ability to perform percentage calculations
  • Familiarity with voltage reduction concepts
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  • Learn about Ohm's Law applications in electrical circuits
  • Study the effects of voltage reduction on current and resistance
  • Explore practical examples of resistance calculations in electrical devices
  • Investigate the implications of power loss due to voltage drops
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Electrical engineering students, technicians working with electrical devices, and anyone involved in circuit analysis and design will benefit from this discussion.

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Homework Statement


If the resistance of the device were reduced by 15.8 percent, what current would be drawn at 120 V?

there was a first part of this question which i have already gotten. the question was
An electrical device draws 2.56 A at 120 V. If the voltage drops by 15.8 percent, what will be the current, assuming nothing else changes? so the resistance is 46.875


Homework Equations


ok so i believe that i would just do 120/(.158x46.875)


The Attempt at a Solution


when i did this i got like 16 A and it was said to be wrong. i am confused on what i did wrong.
 
Physics news on Phys.org
Reducing by 15% means you keep 85% of the resistance. Multiply by .842, not .158.
 

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