Also Calculate dy/dx of the following function
y= (6x^2+x) (4x-x^2)
Ok, I can give you some hints with this one.
You have two options:
1. Multiply (6x^2+x) (4x-x^2) out then take the derivative.
2. Use product rule
Hint for product rule let f(x)=(6x^2+x) and g(x)=(4x-x^2) then use the following formula
(dy/dx)=f '(x)g(x) + f(x)g '(x)
The first option may sound like the easy way out but don't depend on it completely.
What if you had to find (dy/dx) of y=(x^2)(Ln(x))
Now you have no choice but to use the second option and the formula.
Also, I would like for you to actually know what a derivative is.
What is a derivative? You need to know this.
I'm going to say it right here so NEVER forget it.
A derivative is the instantaneous slope on a graph at a specific point.
There are other explanations but at least know that one.
We also need to talk about (dy/dx)
What does (dy/dx) mean?
You can read it as the derivative of y with respect to x.
(dy/dx) is actually an implicit differentiation.
And don't forget that you can also call (dy/dx) as y '