Finding the partial derivative from the given information

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SUMMARY

The discussion centers on calculating the partial derivative of a function z defined as z = f(g(3r^3 - s^2, re^s)). The multi-variable chain rule is applied, specifically dz/dr and dz/ds, using provided derivatives: (dx/dr) = 9r^2, (dx/ds) = -2s, (dy/dr) = e^s, and (dy/ds) = re^s. The key insight is that to find dz/dg, knowledge of the function f(g) is necessary, but the required derivatives at the point of interest can be utilized instead. The final values for the derivatives are 42 and -24.

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Amadeo
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Homework Statement
see post
Relevant Equations
dz/dr = dz/dx (dx/dr) + dz/dy(dy/dr)
problem13.PNG


It seems that the way to combine the information given is

z = f ( g ( (3r^3 - s^2), (re^s) ) )

we know that the multi-variable chain rule is

(dz/dr) = (dz/dx)* dx/dr + (dz/dy)*dy/dr

and

(dz/ds) = (dz/dx)* dx/ds + (dz/dy)*dy/ds

---(Parentheses indicate partial derivative)

other perhaps useful information

(dx/dr)= 9r^2
(dx/ds)=-2s
(dy/dr)=e^s
(dy/ds)=re^s

I don't know how to apply this information because, usually, there is only one variable, like t, being fed into the multi-input function, and the chain rule works nicely. But here we have r and s being fed into the multi-input function g. Further, g is the input of the function f, which is z. In order to obtain the derivative of z with respect to g, we would need to know the function f(g). It is not given. I would guess that the way to find the derivative of z with respect to r would be to multiply the derivative of z with respect to g by the derivative of g with respect to x, multiplied by the derivative of x with respect to r, plus the derivative of z with respect to g multiplied by the derivative of g with respect to y, multiplied by the derivative of y with respect to r.

So that is where I am on this. Thanks for any assistance.
 
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Amadeo said:
here we have r and s being fed into the multi-input function g.
So apply the Relevant Equation you listed, with g in place of z.
Amadeo said:
g is the input of the function f, which is z. In order to obtain the derivative of z with respect to g, we would need to know the function f(g).
No, you only need to know the appropriate derivatives at the point of interest. You are given some values for gx, gy and f' (i.e., fg).
 
Thank you. got it.

42, -24.
 

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