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My professor just asked us a question that I can't get my head around. So we have the original vector in Cartesian format, <y^2,z^2,x^2>

Then I am asked to convert to cylindrical coordinates:

z= z;

θ==arctan(z^2/y^2);

r = \sqrt(y^4+z^4)

However , I am then asked to take the divergence and curl of these items, I have the formula for both but I dont know how to fit them in!

∇⋅v=1r∂∂r(rvr)+1r∂vθ∂θ+∂vz∂z

∇×v=(1r∂vz∂θ−∂vθ∂z)r^+(∂vr∂z−∂vz∂r)θ^+(1r∂∂r(rvθ)−1r∂vr∂θ)z^

For example, for div in tems of r, 1r∂∂r(r(sqrt(z^4+y^4))) which doesnt seem to work

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# Calculate divergence of <y^2,z^2,x^2> in cylindrical coords

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