Calculate Electric field from two point charges

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SUMMARY

The discussion focuses on calculating the electric field generated by two point charges, q1=2x10^-5 C and q2=-4x10^-3 C, located at coordinates (1,3,-1) and (-3,1,-2) respectively. The electric field E at the point (3,1,-2) is derived using the formula E=(1/4πE0)(-qr1/r1^3 + qr2/r2^3). Participants clarify the implementation of this equation in Cartesian coordinates, emphasizing the need to compute the vector distances and their magnitudes for accurate calculations.

PREREQUISITES
  • Understanding of electric field calculations using Coulomb's law
  • Familiarity with vector mathematics in three-dimensional space
  • Knowledge of Cartesian coordinate systems
  • Basic principles of electrostatics
NEXT STEPS
  • Study the application of Coulomb's law in three-dimensional space
  • Learn how to compute vector magnitudes and directions in Cartesian coordinates
  • Explore the concept of superposition of electric fields from multiple charges
  • Investigate the role of permittivity (E0) in electric field calculations
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Students in physics, electrical engineering, or anyone interested in understanding electrostatics and electric field calculations involving multiple point charges.

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[SOLVED] Calculate Electric field from two point charges

Homework Statement



Two point charges with q1=2x10^-5 and q2=-4x1-^-3 are located in free space at (1,3,-1) and (-3,1,-2), respectively, in a cartesian coordinate system. Calculate the electric field E at (3,1,-2)

Homework Equations



E=(1/4piE0)(-qr1/r1^3+qr2/r2^3)

The Attempt at a Solution



I understand the above equation but am unsure of how to implement it using cartesian coords?
 
Last edited:
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The distance between two points is:

s = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}
 
how do i use the vector in this part of the equation though?

q1r1/r1^3

the r1 on top is still a vector...

and then i presume for the bottom part i just take the magnitude of r1 and cube it?
 
Well I've given you the magnitude of the vector so what do you imagine its components to be?
 
just (x,y,z) surely?
 
Make that: ((x_1-x_2) \mathbf{\hat{i}}+...) etc.
 
Awesome, thanks!
 

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