Calculate Electrostatic Force: Metal Spheres 3.00x10^-6C & 2.00x10^-6C @12.0cm

Click For Summary
SUMMARY

The discussion focuses on calculating the electrostatic force between two metal spheres with charges of -3.00x10^-6C and +2.00x10^-6C, positioned 12.0 cm apart. The correct formula used is Fe=kq1q2/r^2, where k is Coulomb's constant (8.99x10^9 N m²/C²). The initial calculation yields 3.75 N, but the correct answer, after accounting for charge transfer when the spheres touch, is 1.56x10^-1 N. The key takeaway is that charge redistribution must be considered before applying the formula.

PREREQUISITES
  • Understanding of Coulomb's Law
  • Familiarity with electrostatic charge concepts
  • Basic knowledge of electric force calculations
  • Ability to manipulate scientific notation
NEXT STEPS
  • Study the principles of charge conservation during contact
  • Learn about the implications of charge redistribution on electrostatic forces
  • Explore advanced applications of Coulomb's Law in different geometries
  • Investigate the effects of medium on electrostatic force calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatic interactions and force calculations in charged objects.

Aamun
Messages
10
Reaction score
0

Homework Statement


A metal sphere with a negative charge of 3.00x10^-6C is placed 12.0 cm from another similar metal sphere with a positive charge of 2.00x10^-6C. The two spheres momentarily touch, then return to their original positions. Calculate the electrostatic force acting on the two metal spheres.


Homework Equations



Fe=kq1q2/r^2

The Attempt at a Solution



Fe=(8.99x10^9)(3.00x10^-6)(2.00x10^-6)/(.12^2)
Fe=3.75 N [Repulsive]

For some reason the above formula won't work to get the answer that it says, am I doing something wrong?

Answer should be 1.56x10^-1 N [Repulsive]
 
Physics news on Phys.org
what happends when the 2 charges touch? Charge is transferred, therefore you have to find out the final charge on eache sphere before you can use the formula.
 
Oh yeah! Ok thanks I got it now!
 

Similar threads

Replies
21
Views
2K
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K