Calculate equivalent resistance

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Homework Help Overview

The discussion revolves around calculating the equivalent resistance between two points, O and N, in a circuit represented by a circular wire with multiple paths. The problem involves analyzing the flow of current through these paths and determining the total resistance based on the configuration of the circuit.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the symmetry of the circuit and the equipotential nature of certain points. There are attempts to calculate the equivalent resistance using various paths and configurations, with some questioning the validity of the reasoning presented.

Discussion Status

Some participants express agreement with the initial calculations, while others challenge the correctness of the provided answer key, suggesting discrepancies in the reasoning. The discussion reflects a mix of confirmations and doubts regarding the assumptions made about current flow in specific paths.

Contextual Notes

Participants note that the official answer key presents different values for the equivalent resistance, leading to confusion and further questioning of the assumptions regarding current distribution in the circuit.

Vibhor
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Homework Statement



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Homework Equations

The Attempt at a Solution



In the attached image the outer circular wire is represented as N . We have to find the equivalent resistance between O and N . Consider a battery of voltage V between O and N . From O there are six similar paths OA ,OB,OC,OD,OE,OF . Now , All six points would be equipotential . Consider any point , say A . No current would flow between A and B . From A there are three paths AX, AN,AY . AX and AY are symmetric w.r.t to AN so current would flow from A to X and then from X to N . Similarly current would flow from A to Y to N . Current would flow directly from A to N .I have drawn the currents in attached image .

Resistance between A and N would be 2r || r || 2r = r/2 .Resistance between O and N via A would be r+r/2 = 3r/2 . Now there are six similar parallel paths from O to N .Hence equivalent resistance would be r/4 .

Is that correct ? Is the reasoning also valid ?

Many Thanks
 

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Vibhor said:

Homework Statement



View attachment 211076

Homework Equations

The Attempt at a Solution



In the attached image the outer circular wire is represented as N . We have to find the equivalent resistance between O and N . Consider a battery of voltage V between O and N . From O there are six similar paths OA ,OB,OC,OD,OE,OF . Now , All six points would be equipotential . Consider any point , say A . No current would flow between A and B . From A there are three paths AX, AN,AY . AX and AY are symmetric w.r.t to AN so current would flow from A to X and then from X to N . Similarly current would flow from A to Y to N . Current would flow directly from A to N .I have drawn the currents in attached image .

Resistance between A and N would be 2r || r || 2r = r/2 .Resistance between O and N via A would be r+r/2 = 3r/2 . Now there are six similar parallel paths from O to N .Hence equivalent resistance would be r/4 .

Is that correct ? Is the reasoning also valid ?

Many Thanks
That all looks right to me.
 
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haruspex said:
That all looks right to me.

Thanks for confirming .

But official key states r/6 as the answer :eek: .
 
Vibhor said:
Thanks for confirming .

But official key states r/6 as the answer :eek: .
That is clearly wrong. We could connect ABCDEF with a zero resistance, and the effective resistance from O to there would be r/6. There must be something to add to get to N.
 
haruspex said:
That is clearly wrong. We could connect ABCDEF with a zero resistance, and the effective resistance from O to there would be r/6. There must be something to add to get to N.

Right .

Sorry , I had read answer of some other question in the key o:) .

Answer key states answer as r/3 .Solution says there would be no current in AX , XN , AY, YN wires . Current would flow from O to A and from A to N . Resistance between O and N would be 2r . Hence equivalent resistance is r/3 .
 
Vibhor said:
Solution says there would be no current in AX , XN , AY, YN wires .
Again, clearly false.
 
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