1. The problem statement, all variables and given/known data Dry-bulb Temperature 46'C Wet-bulb Temperature 34'C P=101.3kPa with these, I have to 'calculate' Specific Humidity(w), Relative humidity(φ), Specific Enthalpy(h) 2. Relevant equations Specific Humidity w=0.622*Pv/Pa when Pa=P-Pv Relative Humidity φ=w*P/[(0.622+w)*Pg] Specific Enthalpy h=ha+w*hg for this problem, I used approximated values based on temperature for ha. so ha=1.005[kJ/KgC]*T[C] ha[kJ/KG] 3. The attempt at a solution P is 101.3 T is 46'C from Table A-4, Pv is 10.14kPa at 46'C w=(0.622*10.14)/(101.3-10.14)=0.069 6.9% φ=0.069*101.3/[(0.622+0.069)*10.14)=0.9976 99.76% this is when I start to feel a bit weird h=1.005*46+0.069*2584.18 =224.54kJ/kg Then I checked my Psychrometric Chart, and found out this makes no sense. Where did I go wrong? or am I reading the the chart wrong?