Calculate Initial Velocity of Object Thrown Vertically

AI Thread Summary
To calculate the initial velocity of an object thrown vertically to a height of 30.0 m, the relevant equations involve kinematics and conservation of energy. The gravitational acceleration is 9.81 m/s², and at the peak height, the final velocity (Vf) is 0 m/s. Using the kinematic equation Vf² = Vi² + 2ad, where 'a' is the acceleration due to gravity and 'd' is the height, allows for solving the initial velocity (Vi). The mass of the object is irrelevant for this calculation, as the energy and kinematic equations yield the same result regardless of mass. This approach provides a clear method to determine the initial velocity needed to reach the specified height.
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An object is thrown vertically into the air and reaches a height of 30.0 m. Neglecting air friction, what was the object’s initial velocity?

What would the equation be for this question?

I know that:

Height: 30.0m
Gravity: 9.81m/s

I'm not quite sure what else I need to figure this out? thank! :)
 
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Is this a trick question where its 0m/s?
 
The easiest way would be to use conservation of energy:
E = 1/2mv^2+mgh
Alternatively, you could use the equation of motion for the object. You know it has a constant acceleration g downwards.
 
Thank you! so would it look something like this:

E=1/2 (230kg)(0.02ms) ^2 + (230kg)(9.81m/s)(32m)

0.092 + 77201.6 = 77201 ?
 
oops i mean

5.43 + 72201.6 = 72207.03
 
The power behind conservation of energy is that you can use the equation for E at any point in the objects trajectory and you will always get the same answer.
You haven't been given the mass of the object, but the answer will be independent of the objects mass anyway.

You have two special points in the objects trajectory which are important to your question. Which are those and what is the expression for the energy at those points?
 
gravity, height and time?
 
I think using Vf^2=Vi^2 + 2ad would be better..Since the highest point is 30 that means at that point v equals 0.
 
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