Calculate Instantaneous Voltage of 50 Hz 3-Phase Supply - 100 V

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SUMMARY

The discussion focuses on calculating the instantaneous voltage of a 50 Hz three-phase AC supply with a peak voltage of 100 V at a specific time of 7.5 ms. The standard equation for a sine wave, V = A*cos(wt + θ), is highlighted, where A represents the amplitude, w is the angular frequency in radians, and θ is the phase shift. Participants emphasize that in a three-phase system, the voltages are evenly spaced across the unit circle, leading to a phase difference of 120 degrees between each phase. This understanding is crucial for accurately determining the instantaneous voltage for each phase.

PREREQUISITES
  • Understanding of AC waveforms and sine waves
  • Knowledge of angular frequency and phase shift
  • Familiarity with three-phase electrical systems
  • Basic trigonometry for calculating cosine values
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  • Learn how to calculate instantaneous voltage in three-phase systems
  • Study the concept of angular frequency and its application in AC circuits
  • Explore the relationship between phase difference and voltage in three-phase supplies
  • Investigate graphical representations of AC waveforms for better visualization
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Electrical engineers, students studying power systems, and professionals working with three-phase AC circuits will benefit from this discussion.

DunceKirchhoff
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A 50 Hz ac three phase supply has a peak voltage of 100 V. Calculate the instantaneous voltage of each phase at a time of 7.5 ms.

Looked all over google and can't seem to find an equation for this?

Can anyone point me in the right direction?
 
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DunceKirchhoff said:
A 50 Hz ac three phase supply has a peak voltage of 100 V. Calculate the instantaneous voltage of each phase at a time of 7.5 ms.
Can you attach a pic of the illustration that accompanied this question?
 
Think about what an AC waveform is. Its a sine wave. the standard form for a sine wave is

V=A*cos(wt+theta) where A=amplitude, w=frequency in radians, & theta=delay.

note with a 3phase system the voltages are evenly out of phase with one another, so they are evenly spread across the unit circle (360 degrees)

Using this information give it another try
 

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