Calculate Kinetic Friction Coefficient for Hockey Puck on Ice

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To calculate the coefficient of kinetic friction for a hockey puck sliding on ice, the puck's initial speed is 21.9 m/s, and it stops after sliding 209.7 m, resulting in an acceleration of -1.14 m/s². The frictional force can be expressed as F(friction) = mu * Normal force, where mu is the coefficient of kinetic friction. The normal force equals the weight of the puck, which can be simplified by assuming a mass of 1 kg for calculations. By linking the equations for friction and acceleration, the coefficient of kinetic friction can be determined. This approach allows for solving the problem effectively using the provided data.
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A hockey puck on a frozen pond with an initial speed of 21.9 m/s stops after sliding a distance of 209.7 m. Calculate the average value of the coefficient of kinetic friction between the puck and the ice.

F(friction)=mu*Normal force
Vf^2=Vi^2+2a(Xf-Xi)

I used the second equation I gave to find the acceleration which is -1.14 m/s^s. I don't know what to do to get the answer from there.
 
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kopinator said:
A hockey puck on a frozen pond with an initial speed of 21.9 m/s stops after sliding a distance of 209.7 m. Calculate the average value of the coefficient of kinetic friction between the puck and the ice.

F(friction)=mu*Normal force
Vf^2=Vi^2+2a(Xf-Xi)

I used the second equation I gave to find the acceleration which is -1.14 m/s^s. I don't know what to do to get the answer from there.

What is the Normal Reaction Force equal to?

How can you work out the Deccelerating Force?

Can you link those to together into 1 equation and then solve it? You'll need to assume the mass equals 1 or cancel them out.
 
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