Calculate Larmor Freq. for Electron in n=2 of Hydrogen Atom

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SUMMARY

The discussion focuses on calculating the Larmor frequency for an electron in the n=2 state of a hydrogen atom under an external magnetic field of intensity B=1T. The Larmor frequency is defined by the equation ωLarmor = eB/(2me), where e is the charge of the electron and me is the mass of the electron. The participant also explores the relationship between the magnetic energy levels and the quantum number m, concluding that the allowed values for m in this state are -1, 0, and 1. The participant successfully derives the Larmor frequency by relating the energy difference ΔE to the frequency ν using the equation ΔE = hν.

PREREQUISITES
  • Understanding of quantum mechanics, specifically quantum states and quantum numbers.
  • Familiarity with the concept of magnetic fields and their effects on charged particles.
  • Knowledge of the Larmor precession and its mathematical formulation.
  • Basic understanding of energy quantization in atomic systems.
NEXT STEPS
  • Study the derivation and implications of the Larmor frequency in quantum mechanics.
  • Explore the Zeeman effect and its relationship with magnetic fields and atomic transitions.
  • Learn about the significance of the quantum number m and its role in determining energy levels.
  • Investigate the applications of Larmor frequency in magnetic resonance imaging (MRI) and spectroscopy.
USEFUL FOR

Students of quantum mechanics, physicists interested in atomic structure, and researchers exploring magnetic effects on atomic systems will benefit from this discussion.

fluidistic
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Homework Statement


Calculate Larmor frequency and the allowed values of the magnetic energy for an electron in a state n=2 of an hydrogen atom. Consider that there's an external magnetic field of intensity B=1T.


Homework Equations


No idea. I don't have any info on this in my classnotes. So I checked out http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/larmor.html#c1 but I get lost.


The Attempt at a Solution


From my understanding, in the state n=2 the electron can have either a "spin up" or "spin down" (though I never learned yet what is the spin). What I understand from my reading is that if there's an external magnetic field, the electron will suffer a torque and "precess" with the Larmor frequency. But I don't know how to relate this with the state n=2 in the hydrogen atom.
According to hyperphysics: \omega _{\text {Larmor}}=\frac{eB}{2m_e}.
 
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Spinnor said:
I appreciate your help but there's nothing that can help me there I think. I know that the magnetic field will causes more emission/absorption lines due to Zeenman effect but there's nothing said for "Larmor frequency" in wikipedia and the pictures of the links.
In hyperphysics I found the equation \Delta E = m_l \mu _B B. Not sure this can help me. I also found \Delta E =g_L m_j \mu _B B.
I'm actually totally lost.
 
I think I got it.
Electron in state n=2 means that the quantum number m can only be -1,0 or 1.
Now I use the fact that \Delta E = \mu _B mB. So I take m=1 for example so I get the value of \Delta E. Then I also know that \Delta E = h \nu. I just have to solve for \nu, this is Larmor frequency.
If I said something wrong please let me know.
 

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