Calculate Larmor Freq. for Electron in n=2 of Hydrogen Atom

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Homework Help Overview

The discussion revolves around calculating the Larmor frequency and the magnetic energy values for an electron in the n=2 state of a hydrogen atom, under the influence of an external magnetic field of 1T.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to relate the concept of Larmor frequency to the electron's state in the hydrogen atom, expressing confusion about the role of spin and torque in this context. Some participants share links to resources about the Zeeman effect, while others question the relevance of these resources to the Larmor frequency. One participant suggests using the quantum number m to calculate energy differences and relates it to frequency.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relationship between energy differences and frequency, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants note a lack of information in class notes regarding the Larmor frequency and express uncertainty about the definitions and relationships involved in the problem.

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Homework Statement


Calculate Larmor frequency and the allowed values of the magnetic energy for an electron in a state n=2 of an hydrogen atom. Consider that there's an external magnetic field of intensity B=1T.


Homework Equations


No idea. I don't have any info on this in my classnotes. So I checked out http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/larmor.html#c1 but I get lost.


The Attempt at a Solution


From my understanding, in the state n=2 the electron can have either a "spin up" or "spin down" (though I never learned yet what is the spin). What I understand from my reading is that if there's an external magnetic field, the electron will suffer a torque and "precess" with the Larmor frequency. But I don't know how to relate this with the state n=2 in the hydrogen atom.
According to hyperphysics: \omega _{\text {Larmor}}=\frac{eB}{2m_e}.
 
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Spinnor said:
I appreciate your help but there's nothing that can help me there I think. I know that the magnetic field will causes more emission/absorption lines due to Zeenman effect but there's nothing said for "Larmor frequency" in wikipedia and the pictures of the links.
In hyperphysics I found the equation \Delta E = m_l \mu _B B. Not sure this can help me. I also found \Delta E =g_L m_j \mu _B B.
I'm actually totally lost.
 
I think I got it.
Electron in state n=2 means that the quantum number m can only be -1,0 or 1.
Now I use the fact that \Delta E = \mu _B mB. So I take m=1 for example so I get the value of \Delta E. Then I also know that \Delta E = h \nu. I just have to solve for \nu, this is Larmor frequency.
If I said something wrong please let me know.
 

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