Calculate Line Integral for a Function on a Level Surface | Homework Equations

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To calculate the line integral of the gradient of a function f(x,y,z) over a curve C on the level surface f(x,y,z) = 5, it is established that the integral grad f dot dr equals f(q) - f(p). Since both endpoints p and q lie on the level surface, f(p) and f(q) are both equal to 5, resulting in the integral being 0. The discussion clarifies that while f(x,y,z) equals 5 on the level surface, the gradient grad f is not zero everywhere on that surface. This distinction is crucial for understanding the behavior of the function and its gradient in this context. Overall, the integral evaluates to zero due to the properties of level surfaces.
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Homework Statement



Let f(x,y,z) be a function of three variables. Suppose that C is an oriented curve lying on the level surface f(x,y,z) = 5. Find the integral grad f dot dr.

Homework Equations





The Attempt at a Solution



integral grad f dot dr = integral f(q) - f(p)

not sure what to do
 
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If a point p is on the level surface f(x,y,z) = 5, what does that tell you about f(p)?
 
If the curve you are integrating over lies on the surface f(x,y,z)=5, then surely the endpoints p and q do as well right?...So f(p)=___? and f(q)=___?
 
f(P) - f(Q) = 5 - 5 = 0
 
is that correct
 
It's correct.
 
If f(x,y,z) = 5, how is grad f not equal to (0,0,0)? Jeez, today's just not my day.
 
f(x,y,z) = 5 on the level surface, not everywhere. If it was equal to 5 everywhere, grad f would be zero.
 
Oh yeah, duh. I think I need to drink more water or something.
 

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