What is the magnitude of the impulse

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    Impulse Magnitude
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SUMMARY

The magnitude of the impulse on the wall from a ball with a mass of 150 g, striking at a speed of 5.2 m/s and rebounding with 50% of its initial kinetic energy, is calculated to be 1.3 N·s. The impulse (I) is derived from the change in momentum (ΔP), which is influenced by the initial and final kinetic energies. The initial kinetic energy (KE) is determined using the formula KE = 1/2 m v^2, leading to the necessary calculations for impulse.

PREREQUISITES
  • Understanding of impulse and momentum concepts (I = ΔP)
  • Knowledge of kinetic energy calculations (KE = 1/2 m v^2)
  • Familiarity with basic physics equations and units
  • Ability to perform unit conversions (grams to kilograms)
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  • Review the principles of impulse and momentum in physics
  • Learn how to calculate kinetic energy before and after collisions
  • Study the conservation of energy in elastic and inelastic collisions
  • Explore practical applications of impulse in real-world scenarios
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to explain impulse and momentum concepts effectively.

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Homework Statement


a ball having a mass of 150 g strikes a wall with a speed of 5.2 m/s and rebounds with only 50% of its initial kinetic energy. what is the magnitude of the impulse on the wall from the ball?


Homework Equations


I=Ft
I=ΔP
KE= 1/2 m v^2


The Attempt at a Solution


the answer is 1.3 N s but i don't know how to get there.
 
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What was its kinetic energy before hitting the wall? What was its kinetic energy after rebounding?

Chet
 

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