Calculate Magnitude of Torque for Flywheel

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SUMMARY

The discussion focuses on calculating the torque required to accelerate a flywheel with a diameter of 1.10 m and a mass of 510 kg from rest to 4.00 x 103 revolutions per minute in 2.85 minutes. The moment of inertia (I) is calculated using the formula I = mR2, resulting in 154.275 kg·m2. The torque (τ) is then determined using τ = Iα, yielding a value of 377.819 Nm. However, the initial answer provided was incorrect, indicating a need for careful verification of calculations.

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Homework Statement



Massive spinning flywheels (disks) can be used for storing energy. Consider a flywheel with a diameter of 1.10 m and a mass of 510 kg. A constant force of magnitude F is applied tangentially to the rim of the flywheel to accelerate it from rest to 4.00 x 103 rev/min during 2.85 min.

(b) What magnitude of torque is necessary to cause this angular acceleration?

Homework Equations



I = mR^{2}
\tau = I\alpha

The Attempt at a Solution



I = mR^{2}
I = (510kg)\ast(.55m)^{2}
I = 154.275 kgm^{2}

\tau = I\alpha
\tau = (154.275kgm^{2})\ast(2.449rad/s^{2}
\tau = 377.819 Nm

The answer was incorrect. Also the angular acceleration was derived from part a and is the correct number. Thanks for the help.
 
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the Tau and Alpha symbols are not suppose to be superscripts. i screwed up the tex
 

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