Calculate Min Distance of 2 Electrons Fired at Speed v

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Homework Help Overview

The problem involves two electrons being fired towards each other at a speed v, with the goal of determining the minimum distance they will reach during their interaction. The context includes concepts from electrostatics and energy conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy principles and relates electric potential energy to kinetic energy. Some participants question the application of these principles and the assumptions made regarding initial conditions.

Discussion Status

The discussion is ongoing, with some participants suggesting that the electric potential energy approach is valid, while others are exploring the implications of conservation of energy in this context. There is no explicit consensus yet, and the original poster is seeking clarification on discrepancies with textbook answers.

Contextual Notes

The original poster notes a difference between their derived formula and the answer provided in their textbook, indicating a potential misunderstanding or misapplication of the concepts involved.

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electron together

2 electrons are fired at speed v towards one another. Knowing that each electron has a charge of e an mass m, what is the minimum distance that the two electrons will reach after fired at one another?

My book has a different answer than me so I have to check with you guys.

I wrote, -dE = dEk

-(E2 - E1) = (Ek2 - Ek1) - Ek2 is zero to for minimizing radius, and we assume E1 to be zero.

E2 = Ek1

2ke^2/r =mv^2

2ke^2 / mv^2 = r

Now in our book, they had this question with numbers, i derived this formula and plugged in my values and it didn't match the answer in the book.
 
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i never get any answers here man :(
 
no luck?
 
It seems that the electric potential energy is correct, but using conservation of energy, that would have to equal the combined initial kinetic energies of the two electrons, which would be 2 * 1/2 mv2 = mv2.
 

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