The problem involves calculating the change in momentum for a two-part firecracker with a total mass of 1.0 kg, launched at a speed of 25 m/s. The firecracker separates into two equal parts at an angle of 7.5° after launch, maintaining the same speed. Participants are exploring the implications of momentum conservation and vector components in this context.
The discussion is ongoing, with participants attempting to clarify their understanding of momentum components and the effects of the angle of separation. Some guidance has been offered regarding the calculations, but there is still uncertainty about the correct approach to determining the change in momentum.
Participants are working under the assumption that air friction is negligible. There is also a focus on ensuring that the calculations reflect the correct mass of the firecracker parts and their respective velocities before and after separation.
mfb said:The sine is not the right trigonometric function...
The right function will give a similar, but not the same result.
Yes (Good catch mfb.) But you need all three items in the answer: the direction, the numerical magnitude and the units. If you omit any of those it could be marked wrong.Lacnez said:alright i did 12.5tan7.5 = 1.6457 kg m/s