Calculate Momentum Change for a 1.0 kg Firecracker at 25 m/s Launch Speed

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SUMMARY

The discussion centers on calculating the change in momentum for a firecracker with a mass of 1.0 kg launching at 25 m/s, which separates into two equal parts at a 7.5° angle. The original momentum is calculated as 25 kg m/s, and the momentum of each part post-separation is determined to be approximately 1.6457 kg m/s in the horizontal direction. The change in momentum for each part is derived from the difference in momentum before and after separation, emphasizing the importance of vector components in momentum calculations.

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  • #31
Don't add.

There is a different problem:
mfb said:
The sine is not the right trigonometric function...
The right function will give a similar, but not the same result.
 
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  • #32
alright i did 12.5tan7.5 = 1.6457 kg m/s
 
  • #33
Lacnez said:
alright i did 12.5tan7.5 = 1.6457 kg m/s
Yes (Good catch mfb.) But you need all three items in the answer: the direction, the numerical magnitude and the units. If you omit any of those it could be marked wrong.
 
  • #34
alright thanks a lot guy I apologize for the inconvenience I'm doing this course all online and no one to help or teach it to me so it's not the greatest thing.

Thanks again
 

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