Calculate ##P(C|A')## in the given probability problem

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The discussion focuses on calculating the conditional probability P(C|A') in a scenario where events A and B are independent but not mutually exclusive. The initial calculation of P(C) is correct at 0.42, but the derived formula for P(C|A') appears to be incorrect, leading to confusion. Participants suggest revisiting the value of P(A ∩ C) to identify the mistake. The independence of events A and C is questioned, indicating that this may affect the calculations. The thread emphasizes the importance of accurately determining the intersection of events in probability problems.
chwala
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Homework Statement
See attached ( textbook question).
Relevant Equations
Understanding of conditional probability
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My interest is on part ##b## only. We know that ##A## and ##B## are independent and not mutually exclusive events therefore,

##P(C)=0.7×0.6=0.42##

##P(C|A')=\dfrac{P(C)-P(A∩C)}{P(A')}=\dfrac{0.42-(0.3×0.42)}{0.7}=\dfrac{0.294}{0.7}=0.42## which is wrong according to textbook solution.

Where is my mistake? cheers.
 

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Revisit what the value of Probability of "A intersect C" is.

Are A and C independent?
 
@scottdave wawawawawawa this was a nice one man! Phew. Seen it...
 

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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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