Calculate Period of Leg of 1.75m Tall Man (68 kg)

[hot2moli]

The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of , where I is the moment of inertia, m is the mass, and h is the distance from the pivot point to the center of mass. The leg can be considered to be a right cylinder of constant density. For a man, the leg constitutes 16 \% of his total mass and 48 \% of his total height.
Find the period of the leg of a man who is 1.75 m in height with a mass of 68 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml^2/3

________sec



Leg=10.88kg AND 0.84m

For the moment of inertia, what is the value for m and l?? is that the mass and length of the entire body?

 

[dynamicsolo]

... The leg can be considered to be a right cylinder of constant density. For a man, the leg constitutes 16 \% of his total mass and 48 \% of his total height.

... The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml^2/3

...

Leg=10.88kg AND 0.84m

For the moment of inertia, what is the value for m and l?? is that the mass and length of the entire body?

The values of m and l that you need are for the leg only, which you are asked to treat as a cylinder swinging about one end; the numbers are the ones you've already calculated.