Period of a Pendulum and moment of inertia

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Homework Help Overview

The discussion revolves around calculating the period of a physical pendulum, specifically a hollow sphere ornament. The problem provides mass, radius, and moment of inertia but lacks the distance L, which is crucial for applying the formula for the period.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of L and its relevance to the problem, questioning how to determine its value given the setup. There are suggestions to consider the geometry of the ornament's attachment and the implications of the loop on the pendulum's behavior.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the setup and the necessary parameters for the calculations. Some guidance is offered regarding the relationship between torque and angular motion, but there is no consensus on a definitive approach yet.

Contextual Notes

There is a noted confusion regarding the attachment of the ornament, with some participants initially misinterpreting the nature of the connection to the tree limb. This may affect the understanding of the distance L needed for calculations.

Quincy
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Homework Statement



A holiday ornament in the shape of a hollow sphere with mass 1.0×10−2 kg and radius 5.0×10−2 m is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum. Calculate its period. (You can ignore friction at the pivot. The moment of inertia of the sphere about the pivot at the tree limb is (5/3)MR^2.)

Homework Equations



T = 2Pi*(sqrt(I/mgL))

The Attempt at a Solution



This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?
 
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You're given enough info to figure out what L is. Think about what exactly L is defined as. It's the distance between what two points?
 
Quincy said:

Homework Statement



A holiday ornament in the shape of a hollow sphere with mass 1.0×10−2 kg and radius 5.0×10−2 m is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum. Calculate its period. (You can ignore friction at the pivot. The moment of inertia of the sphere about the pivot at the tree limb is (5/3)MR^2.)

Homework Equations



T = 2Pi*(sqrt(I/mgL))

The Attempt at a Solution



This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?

I think it is saying that it is not hanging. It is attached by a loop. Draw a loop around the limb and then draw the ornament attached to the loop.
 
Hi Quincy! :smile:

(have a square-root: √ and a pi: π and try using the X2 tag just above the Reply box :wink:)
Quincy said:
This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?

Then invent a formula! :wink:

Find the torque (moment) of the weight at a typical angle, and then use the formula τ = Iα to get an (approximately) shm equation. :smile:
 
tiny-tim said:
Hi Quincy! :smile:

(have a square-root: √ and a pi: π and try using the X2 tag just above the Reply box :wink:)


Then invent a formula! :wink:

Find the torque (moment) of the weight at a typical angle, and then use the formula τ = Iα to get an (approximately) shm equation. :smile:


Wouldn't you still need that distance for I?
 
vela said:
You're given enough info to figure out what L is. Think about what exactly L is defined as. It's the distance between what two points?

Oops, I misread the problem, I was thinking it was attached to a wire with some length instead of a loop.
 

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