Calculate Repulsive Force of 2 Protons in Atom

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SUMMARY

The repulsive force between two protons in an atomic nucleus, separated by a distance of 1.00 x 10^-15 meters, is calculated using Coulomb's Law. The formula applied is F = k |q(1)|^2 / r^2, where k is the Coulomb's constant (8.99 x 10^9 N m²/C²) and q(1) is the charge of a proton (1.602 x 10^-19 C). The resulting force is 230.7 N, confirming the calculation's accuracy despite minor formula notation errors.

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lilkrazyrae
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Find the repulsive force on two protons in the nucleus of an atom assuming they are separated by the minimum distance of 1.00 x 10^-15m.

So F=k lq(1)l^2/ r^2
=8.99 x 10^9 (1.602 x 10 ^-19)^2/(1.00 x 10^15m)
=230.7N

Is this correct?
 
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lilkrazyrae said:
Is this correct?

Answer looks right to me, though you made several mistakes in writing out the formula. :-p
 

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