1. The problem statement, all variables and given/known data In a certain organic molecule, the nuclei of 2 carbon atoms are separated by a distance of .20nm, What is the magnitude of the electric repulsion between them? Now, I know the distance between them, but it has to be converted into meters: .20nm = .20 X 10 ^-9m And k is a proportionality constant, equaling: 8.99 X 10 ^9. 2. Relevant equations So I am using Coulomb's law for this which states F = (K|q1| |q2|)/r^2 3. The attempt at a solution The only unknowns are q1 and q2. In order to solve for those, I have to know the magnitude of their charge. Since there are 6 protons in a Carbon atom, in order to get the charge I multiply 6 by e, which equals: 1.60X10^-19 C I have solved for all the unknowns, so all that is left is to plug in all the variables and solve for the F. F = (8.99 X 10 ^9 * (6*1.60X10^-19)^2)/(.20 X 10 ^-9m)^2 This gives me the final answer of: 2.07x10^-7 N I wanted to verify that my math and reasoning behind my calculations were correct. Thanks!