Calculate the amount of work required to assemble a system of charges.

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SUMMARY

The discussion focuses on calculating the work required to assemble a system of three point charges (Q1=22.6 µC, Q2=22.6 µC, Q3=61.0 µC) positioned at the corners of an isosceles triangle with sides measuring 4 m and 2 m. The work is calculated using the formula W = ΔPE = qΔV, where the initial voltage (Vi) is zero since the charges are brought in from infinity. The user attempted to compute the work for each charge individually and sum them, but was advised to maintain unit consistency for error-checking.

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ditde
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Homework Statement



The three charges shown below (Q1=22.6*10^-6C, Q2=22.6*10^-6C, Q3=61.0*10^-6C) are at the corners of an iscoceles triangle with sides a=4 m and b=2 m.

Q3 is 2m from Q1 and Q2, Q1 is 4m from Q2. In other words, Q3 is the point charge at the "tip" of the isosceles triangle.

Calculate the amount of work required to assemble this system of charges, assuming they are brought in from infinity.

Homework Equations



W = ΔPE = qΔV = q(Vi-Vf)
V = kQ/r

Being brought in from infinity means that Vi (initial voltage) = 0.

The Attempt at a Solution



I calculated the work required to bring in each charge individually and attempted to add them in the end.

Example of my working;

Work1 = Q1 * (0 - Vf)

Vf = kQ2/r2 + kQ3/r3

Work1 = 22.6*10^-6 * (0-(((9.10^9*22.6*10^-6)/4)+((9.10^9*61.0*10^-6)/2))
 
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ditde said:
I calculated the work required to bring in each charge individually and attempted to add them in the end.
That is fine.
Try to work with units please, it is easier to find errors that way.
 

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