Calculate the Curl of a Velocity vector field

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To calculate the curl of a velocity vector field for a solid object rotating about an axis, it is established that the curl of the velocity field, represented as ∇×v, equals 2ω, where ω is the angular velocity. The discussion highlights the use of Stokes' theorem and suggests employing the relationship v(x,y,z) = ω × (xi + yj + zk) for the solution. Participants emphasize the importance of vector calculus identities, specifically treating ω as a constant vector to simplify calculations. The conversation also requests geometric intuition to better understand the problem. Overall, the focus is on applying mathematical identities to derive the relationship between the curl and angular velocity.
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Homework Statement



The velocity of a solid object rotating about an axis is a field \bar{v} (x,y,z)
Show that \bar{\bigtriangledown }\times \bar{v} = 2\,\bar{\omega }, where \bar{\omega } is the angular velocity.

Homework Equations



3. The Attempt at a Solution [/B]

I tried to use the Stoke's theorem using an infinitesimal element with trapezoidal shape, but i was stuck with calculations. Which is the best way to resolve the equation ? It would be fantastic if you could explain me the geometric intuition behind the problem
 
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Just use the relationship ##\vec{v}(x,y,z)=\vec{\omega}\times(x\vec{i}+y\vec{j}+z\vec{k})## and some identities of vector calculus about the curl operator.

The main identity you ll use is the first one found here : https://en.wikipedia.org/wiki/Curl_(mathematics)#Identities. Notice that you ll treat ##\vec{\omega}## as a constant vector in this identity so it will be ##\nabla\cdot\vec{\omega}=0## , ##\vec{F}\cdot\nabla \vec{\omega}=0## e.t.c
 
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Thanks so much =)
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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