- #1

jlucas134

- 22

- 0

Outside the tube

Inside the tube.

I know how to find the field, its just -"del" V, but my problem is finding V...

I know you have to take into account the area of the surface and the radius b...

here is what I have for the integral, which i don't know is right or not. Any help would be outstanding...If someone could help me set it up, I think i could get it from there.

(Q*k )/h * int (1/R), dz, limit from 0 to h, where R is equal to sqrt(b^2+(p-z)^2)

after integration

I get a

(Q*k )/h ln [(sqrt(b^2+(p-z)^2)+h-p)/(sqrt(b^2+p^2)-p)}

If I can get it set up, I know I can do the integral. Please help.