Calculate the EMF induced in the square?

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SUMMARY

The discussion focuses on calculating the electromotive force (EMF) induced in a rotating square wire of side length 1.4 m within a uniform magnetic field of 1.2 T. The wire rotates about an axis through one corner at an angular speed of 3 revolutions per second. The relevant equation for this calculation is E = N * B * A * ω, where N is the number of turns (1), B is the magnetic field strength (1.2 T), A is the area of the square, and ω is the angular velocity. The area A must be correctly calculated as 1.96 m², and the flux must be analyzed as a function of time due to the rotation.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula E = N * B * A * ω
  • Knowledge of calculating magnetic flux (ψ = B * A)
  • Basic geometry related to rotational motion
NEXT STEPS
  • Study the derivation of the EMF formula in rotating systems
  • Learn about magnetic flux variation with time during rotation
  • Explore the concept of induced EMF in different geometrical configurations
  • Investigate the effects of angular velocity on induced EMF
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Students in physics, particularly those studying electromagnetism, as well as educators and anyone involved in solving problems related to induced EMF in rotating systems.

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Homework Statement



  1. A square of wire with side length 1.4 m rotates about an axis through one corner that is perpendicular to the plane of the square with an angular speed of 3 rev/s. There is a uniform magnetic field of 1.2 T perpendicular to the square. Calculate the EMF induced in the square.

Homework Equations


I know we'll need E=N*B*A*w; here, N=1, B=1.2T, and I thought A=1.96 m2, but I'm not sure now.

The Attempt at a Solution


I attempted to do the equation at face-value but realized my geometry is not correct. How would you set up this problem geometrically? I think the problem should be set up with a square formed by the x and z axis and the axis of rotation at the y, maybe something like the diagram I uploaded. But then how do I form the equation from there?

Thanks for any help in advance!
 

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The flux, ψ = B * A.

E = dψn / dt = dψ / dt , ( N = 1 ).

So calculate the amount of flux, dψ, that the square crosses within a time, dt.
 
How does the B field, and therefore the flux, vary with time as the square rotates around the wire? Your answer will be a function of time (unless you express the emf as rms or peak volts).
 

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