Calculate the frictional torque of the record player

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Homework Help Overview

The discussion revolves around calculating the frictional torque of a record player that is slowing down after the motor is turned off. The problem involves concepts from rotational kinematics and dynamics, specifically focusing on angular speed, torque, and moment of inertia.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial and final angular speeds, attempts to calculate angular acceleration, and the resulting torque. There are questions about the correct moment of inertia for a solid wheel and how to apply it in the torque calculation.

Discussion Status

Some participants have provided calculations and expressed confusion about the results, while others have pointed out potential errors in the moment of inertia used. There is an ongoing exploration of different approaches to the problem, and guidance has been offered regarding the correct formula for the moment of inertia.

Contextual Notes

Participants are working under the constraints of homework rules that discourage providing direct answers. There is also a mention of a separate problem involving a solid sphere rolling down a ramp, indicating a broader context of rotational motion being discussed.

Noor123
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URGENT! rotational kinematics

A record player is spinning at 33 rpm when the motor is switched off. After 5.9 seconds the angular speed has decreased to 20 rpm. Calculate the frictional torque if the record player can be treated as a solid wheel of mass 5.5 kg and radius 14 cm.


A. 1187.62712 Nm
B.0.01244 Nm
C. 0.04752 Nm
D. 2375.25424 Nm
E. 0.11876 Nm


Which one?
 
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Show us your work. We don't give out answers here. We will help you figure it out.
 
omege final = 3.45 rad/sec

omega initial = 2.094 rad/sec

omega final = omega initial + alpha x delta t

2.094 = 3.45 + 5.9 alpha

alpha = -0.230


torque = I x alpha

mR^2 x alpha
(0.1078) (-0.229)
= -0.02468

?? none of these answers
 
Plzz Hurrrrryyyy Folks!
 
You are not using the right moment of inertia. For a solid wheel it should be 0.5MR^2.
 
Ok what about this?

PLZ QUICK

A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15 degrees, and rolls without slipping to the bottom. The upper end of the ramp is 2.7 m higher than the lower end. What is the linear speed of the sphere when it reaches the bottom of the ramp?

A. 132.3 m/s
B. 6.15 m/s
C. 7.27 m/s
D. 7.67 m/s
E. 37.8 m/s


i 've tried PE = 1/2 mv2 + 1/2 Iw2

but nothing worked please HELP!
 
What did you use for I? Did you put w in terms of v?
 

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