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Calculate the kinetic energy of the proton

  1. Apr 15, 2012 #1
    1. The problem statement, all variables and given/known data
    proton (mass = 1.67x10-27kg) is confined in a one dimensional potential well of infinite height and width of 2.847 x10-14m. Calculate the kinetic energy of the proton in the state with quantum number 1 in MeV


    2. Relevant equations
    KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev


    3. The attempt at a solution
    ((6.6E-34^2)*(1^2))/(8*1.67x10-27*2.847 x10-14^2)=1.7368E-14/1.6E-13=.10855
    this answer is wrong, im not sure why or what im doing wrong. please help
     
  2. jcsd
  3. Apr 15, 2012 #2
    when I did your calculation I got 4 x 10^-14/1.6 x 10^-13 = 0.252
    Check your calculation again
     
  4. Apr 15, 2012 #3
    I just checked my calculation again, I came up with 0.252 also. Thank you!
     
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