# Calculate the mass of ice with heat transfer / latent heat

## Homework Statement

Find mi, the initial mass of ice.

Ti = -20
ci = 2093Jkg-1K-1
Ts = +35
ms = 2kg
cs = 837.4Jkg-1K-1
cw = 4187Jkg-1K-1
lf = 3.35x105Jkg-1

S = solid
W = water
I = ice
lf = latent heat of fusion of ice / water

## Homework Equations

Q=mc$$\Delta$$T
Q=C$$\Delta$$T
Q=ml

## The Attempt at a Solution

For the Solid
Qs = (2)(837.4)(10-35)
Qs = -4.187x104J

For the Water / Ice
Qi = mix(4.186x104)
Q = mix(3.35x105)
Qw = mix(4.187x104)

I don't know where to go from here, I have seen the markscheme however and I am aware that the answer is: mi = 0.100kg

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gneill
Mentor
You've specified everything but the experimental circumstances. What are the initial and final conditions? Do you want to calculate the mass of ice remaining, or the initial mass of ice?

Oops, the Solid is placed on top of the ice. The ice then melts and the final temperature of both the solid and the ice is 10. So basically I'm looking for the initial mass of the ice, before the rock was placed onto it.

gneill
Mentor
So, the final temperature is 10C. What does that tell you about the the water in the system?