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Calculate the mass of ice with heat transfer / latent heat

  • Thread starter adam640
  • Start date
  • #1
19
0

Homework Statement



Find mi, the initial mass of ice.

Ti = -20
ci = 2093Jkg-1K-1
Ts = +35
ms = 2kg
cs = 837.4Jkg-1K-1
cw = 4187Jkg-1K-1
lf = 3.35x105Jkg-1

S = solid
W = water
I = ice
lf = latent heat of fusion of ice / water


Homework Equations


Q=mc[tex]\Delta[/tex]T
Q=C[tex]\Delta[/tex]T
Q=ml


The Attempt at a Solution


For the Solid
Qs = (2)(837.4)(10-35)
Qs = -4.187x104J

For the Water / Ice
Qi = mix(4.186x104)
Q = mix(3.35x105)
Qw = mix(4.187x104)

I don't know where to go from here, I have seen the markscheme however and I am aware that the answer is: mi = 0.100kg
 

Answers and Replies

  • #2
gneill
Mentor
20,793
2,773
You've specified everything but the experimental circumstances. What are the initial and final conditions? Do you want to calculate the mass of ice remaining, or the initial mass of ice?
 
  • #3
19
0
Oops, the Solid is placed on top of the ice. The ice then melts and the final temperature of both the solid and the ice is 10. So basically I'm looking for the initial mass of the ice, before the rock was placed onto it.
 
  • #4
gneill
Mentor
20,793
2,773
So, the final temperature is 10C. What does that tell you about the the water in the system?
 

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