Calculate the orbital period of a spacecraft around the moon

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SUMMARY

The discussion focuses on calculating the orbital period of a spacecraft around the Moon using the formula T = 2(pi)(r^(3/2)) / √(GM). The mass of the Moon is specified as 7.35 x 10^22 kg, and its radius is 1.74 x 10^6 m. Participants confirm that the radius of the orbit must include the altitude of 100 km (100,000 m) added to the Moon's radius. The conversation emphasizes the importance of correctly applying the formula and sharing calculation steps for clarity.

PREREQUISITES
  • Understanding of gravitational physics and orbital mechanics
  • Familiarity with the formula T = 2(pi)(r^(3/2)) / √(GM)
  • Knowledge of the mass and radius of celestial bodies, specifically the Moon
  • Basic skills in unit conversion (e.g., kilometers to meters)
NEXT STEPS
  • Research the derivation of Kepler's Third Law of planetary motion
  • Learn about gravitational constants and their application in orbital calculations
  • Explore the effects of altitude on orbital mechanics
  • Investigate real-world applications of orbital period calculations in space missions
USEFUL FOR

Aerospace engineers, astrophysicists, students studying orbital mechanics, and anyone interested in the physics of space travel will benefit from this discussion.

pinkerpikachu
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1. During an Apollo lunar landing mission, the command module continued to orbit the Moon at an altitude of 100km. How long did it take to go around the Moon once?

2. T= 2(pi)(r^3/2) / root (GM)
mass of moon = 7.35 X 10^22
radius of moon= 1.74 X 10^6




3. I think that is the correct equation, and I've tried plugging all the values in. I know that the radius will have the 100km (100,000m) added on to it...right?
 
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pinkerpikachu said:
1. During an Apollo lunar landing mission, the command module continued to orbit the Moon at an altitude of 100km. How long did it take to go around the Moon once?

2. T= 2(pi)(r^3/2) / root (GM)
mass of moon = 7.35 X 10^22
radius of moon= 1.74 X 10^6

3. I think that is the correct equation, and I've tried plugging all the values in. I know that the radius will have the 100km (100,000m) added on to it...right?
Your equation is correct. What are you using for the radius of the orbit?

AM
 
Last edited:
Be sure to include that the radius of the orbit is 100+ radius of the moon in km.
 
Welcome pinkerpikachu to PF forums! You will find this is a great forum for interactive discussion on all kinds of topics.

In your question, you are off to a good start. It would be useful to show us the results of your calculations (and the steps you made to get there). This will enable us to see if you are on the right track.
 
I'm working on the same problem, can you help me understand how you derived your initial equation?
 

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