Calculate the potential difference induced in the circuit as a function of time

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Homework Help Overview

The problem involves a square circuit rotating in a uniform magnetic field, requiring the calculation of the induced potential difference as a function of time. The context is rooted in electromagnetism, specifically Faraday's law of induction.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to differentiate the expression for potential difference but expresses uncertainty about the differentiation process. A participant suggests expressing the angle in terms of time, leading to a revised expression for the potential difference.

Discussion Status

The discussion has progressed with participants confirming the correctness of the derived expression for potential difference after incorporating the time-dependent angle. However, the exploration of the differentiation process and its implications remains open.

Contextual Notes

Participants are working within the constraints of the problem statement, focusing on the relationship between angular motion and electromagnetic induction without additional external information.

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Homework Statement



A square circuit with side L lies in the x-y plane, is centred on the origin and has sides parallel to the x and y axes. At time t=0 it starts turning about the x axis, in a region characterised by a uniform magnetic field B parallel to z, with uniform angular speed omega. By considering the angle between the surface normal and the field, calculate the potential difference (electromotive force) induced in the circuit as a function of time.

Homework Equations



phi(subscript B)=BA cos theta

potential difference=-d(phi (subscript b))/dt

The Attempt at a Solution



potential difference=-d(BA cos theta)/dt

this isn't leading anywhere. I don't know how to differentiate it with respect to t
 
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You need to express the angle theta (angle between surface normal and field lines) in terms of time. (theta starts from 0 degrees)
 
Last edited:
thank you, Pi-bond

potential difference=-d(BA cos omega*t)/dt

=BA omega sin (omega*t)

correct?
 
Yes, that is correct.
 

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