Calculate the radius of gyration for a plane figure

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The discussion focuses on calculating the radius of gyration for a plane figure bounded by the curve xy = 4, the x-axis, and vertical lines at x = 2 and x = 4. Participants clarify the formula for the moment of area, emphasizing the importance of the radius of gyration squared term, which is derived from the geometry of the shape. The radius of gyration for a uniform rod is mentioned as k = √(a^3/3), highlighting the connection to calculus and integration of elementary shapes. There is a consensus on the need to clearly define the axis of rotation for accurate calculations. The conversation underscores the balance between using standard results and deriving formulas from first principles.
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Homework Statement
A plane figure is bounded by the curve xy = 4, the x-axis and the ordinates at x = 2 and x =4. Calculate
Relevant Equations
$$I = Ak^2$$
$$xy=4$$
Limits of x= 2 to x=4
Area of strip = $$/delta x /times y$$

Moment of area for strip $$= Area /times (radius of gyration)^2 $$
$$ = /delta x /times y /times (/frac{y^2}{3})^2 $$

Why is the radius of gyration squared term $$y^2$ over 3? $$
 
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shishykish said:
Homework Statement: A plane figure is bounded by the curve xy = 4, the x-axis and the ordinates at x = 2 and x =4. Calculate
Relevant Equations: $$I = Ak^2$$
$$xy=4$$
Limits of x= 2 to x=4

Area of strip = $$\delta x \times y$$

Moment of area for strip $$= Area \times (radius of gyration)^2 $$
$$ = \delta x \times y \times (\frac{y^2}{3})^2 $$
I have corrected your LaTeX symbols from "/" to "\".
Presumably you meant ## \delta x \times y \times (\frac{y^2}{3})##
shishykish said:
Why is the radius of gyration squared term $$y^2/ 3$$?
What is the radius of gyration of a uniform rod?
 
haruspex said:
I have corrected your LaTeX symbols from "/" to "\".
Presumably you meant ## \delta x \times y \times (\frac{y^2}{3})##
[]
What is the radius of gyration of a uniform rod?
radius of gyration for a uniform rod is $$ k= \sqrt{ \frac{a^3}{3} }$$from what I remember of deriving it from my notes. So we are actually taking this shape as an elementary strip between the limits of 2 to 4. The total moment of area will be the $$ I_{area} = area \times (radius of gyration)^2 $$
 
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shishykish said:
Homework Statement: A plane figure is bounded by the curve xy = 4, the x-axis and the ordinates at x = 2 and x =4. Calculate
Presumably the missing phrase at the end of the sentence is something like: "the radius of gyration about the x-axis".

It is important that the required axis of rotation is clear. For example it could easily be the axis perpendicular to the plane passing through the centre of mass.
 
Ha! Yes it is. I really could learn how to copy and paste properly!
 
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haruspex said:
I have corrected your LaTeX symbols from "/" to "\".
Presumably you meant ## \delta x \times y \times (\frac{y^2}{3})##

What is the radius of gyration of a uniform rod?
Hi! So I should be thinking conceptually in terms of calculus. Taking an elementary shape then summing over the whole object is one of the most basic approaches.
 
shishykish said:
radius of gyration for a uniform rod is $$ k= \sqrt{ \frac{a^3}{3} }$$
That’s dimensionality wrong. Is it a typo?
shishykish said:
So I should be thinking conceptually in terms of calculus.
Yes, but it is ok to use standard results too. In this problem you have a nonstandard 2D shape that can be represented as a collection of 1D standard shapes - thin rectangular strips that can be taken to be so thin as to be 1D rods.
Work from first principles (the radius of gyration of a point mass at a given distance from an axis) and integrate twice, or skip the first integration by quoting the result for a 1D rod.
 
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