Calculate the Second Ionization Energy of Lithium

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SUMMARY

The discussion focuses on calculating the second ionization energy of lithium (Li) using the total energy for the transition from Li to Li3+ at 1.960 x 104 kJ/mol and the first ionization energy of Li at 5.20 x 102 kJ/mol. The participant utilized the equation Etotal = E1 + E2 + E3 to isolate E2 and E3. They calculated the energy for a single electron in Li2+ as -1.962 x 10-17 J but sought clarification on converting this value to ionization energy.

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pasido
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Homework Statement



vMAiZ.png

Given
-Total Energy for Li \rightarrow Li ^{3+} = 1.960 * 10^{4} kJ/mol

-First Ionization Energy of Li = 5.20 * 10^{2} kJ/mol

Homework Equations


Other than the equation in the image, I used the equation:
Etotal = E1 + E2 + E3

The Attempt at a Solution


Since Etotal and E1 are given, I have E2 and E3 left to solve.

To solve for E3, I used the equation in the picture.

Li^2+= A hydrogen atom (1 electron), I used the equation in the picture to solve for the energy for a single electron. Energy = -1.962*10^-17 J

The problem is, I don't know what to do with that number. How do I convert energy of a single electron to ionization energy?
 
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That energy is the energy you need to supply to the electron in order to overcome coulombic forces, i.e. to ionize the species. Simple enough.
 
pasido said:
How do I convert energy of a single electron to ionization energy?

What is a mole?
 

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