Homework Equations/ 3. The Attempt at a Solution [/B]
Here is my attempt at the homework, I'm trying to correct my mistakes and am looking for help in the right direction.
In other words, apply the voltage divider concept? Sure! It's one of the concepts that the problem statements says you're to use.Gotcha, I questioned if that were allowed!
I know from Ohm's law that V=IR so Vab= I*R
And if we know that we start with a rise of 10V until the 2kOhm resisitor, could we find the current, voltage at R1 then use that to find the Voltage at R2?
When you combine resistors in series, you lose a node. But that's okay. Now you have more information than when you started. You know that the voltage at the right-hand side of the 2k resistor is 6.667 V. So just continue from there until you are able to figure out the voltage at node A.So, can you not reduce the circuit at all in this example without losing points A or B?
I think I was editing this just as you were posting your response :)Or is it allowable to reduce from the left side?
e.g. that the 2kOhm and 8kOhm resistors become a 10kOhm resistor, and the 6kOhm and 4kOhm resistor become another 10kOhm resistor?
The idea is that you are reducing the circuit in stages from the left until you are left with a just a voltage divider that contains the original nodes A and B. It may not be obvious that this is the case until after you've done the first iteration.Can I even reduce to it from the right, then? I keep thinking that will just eliminate node A again?