Calculate the work done by the force

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Homework Help Overview

The discussion revolves around calculating the work done by a force on a particle moving along a specified curve in a two-dimensional space. The problem involves parameters such as the force components and the path defined by a quadratic equation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of work in the context of a force acting along a path and consider the integral formulation for calculating work. There are inquiries about the next steps in the calculation process.

Discussion Status

The conversation is ongoing, with participants seeking clarification on how to proceed with the integral calculation of work. Some guidance has been offered regarding the integral setup, but no consensus or complete method has been established yet.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. The specific values for the force components and the curve parameters are provided, but further details on the integration process are not fully explored.

pph1011
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Homework Statement



A particle moves from the origin to the point x=3m, y=6m along the curve y=ax^2 - bx , where a = 2.0m^-1 and b = 4.0m . It is subject to a force F=cxy i + d j , where c= 8.0N/m^2 and d= 16N .

Homework Equations



Calculate the work done by the force

The Attempt at a Solution

 
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pph1011 said:

Homework Statement



A particle moves from the origin to the point x=3m, y=6m along the curve y=ax^2 - bx , where a = 2.0m^-1 and b = 4.0m . It is subject to a force F=cxy i + d j , where c= 8.0N/m^2 and d= 16N .

Homework Equations



Calculate the work done by the force

The Attempt at a Solution


Work is defined as:

[tex]\int\vec{F}d\vec{x}[/tex]. Do you know what's next?
 
what's the next?
 
pph1011 said:
what's the next?

Take the integral of work.

[tex]W=\int Fds \rightarrow W = \int\int F dx dy[/tex]

Catch my drift?
 

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