I have a few questions I need help with on my assignment. I cannot wrap my head around this work and energy chapter.
Anyway here it is;
A 62.7-kg skier coasts up a snow-covered hill that makes an angle of 25.2° with the horizontal. The initial speed of the skier is 8.22 m/s. After coasting 2.09 m up the slope, the skier has a speed of 3.20 m/s. Calculate the work done by the kinetic frictional force that acts on the skis
The Attempt at a Solution
FBD. Fn in the positive y-direction, mgcos(theta) in the negative y-direction, Fk and mgsin(theta) in the negative y-diretion.
WFN=0 ----> makes a 90deg angle with the direction.
WTOT= 0+0+548+WFk = 1/2mVf^2-1/2mVi^2
I am using three sig digits for my calculations. The answer is wrong.