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Calculate thickness of organic layer on wire

  1. Sep 6, 2010 #1
    Hello

    I have done some lab work where I have coated a wire with an organic layer.

    The density of the organic layer is 800kg/m^3 and the density of the wire is 2620kg/m^3. I assume 1wt% of the wire is the organic layer the rest is the wire.

    The mass of the wire with organic layer is 10^(-6)kg. I assume the geometry of the wire is a cylinder with radius 8.5*10^(-6)m.

    What would be the thickness of the organic layer and what volume % will it have of the whole volume?Please comment my code. Is it right what I have done?



    3. The attempt at a solution

    I did the following calculation where I found the thickness of the organic layer to approx 72nm.

    DensitetWire_Organiclayer=800*0.01+2620*0.99; %Density of wire with organic layer

    RadiusWire_Organiclayer=8.5*10^(-6)%:0.5*10^(-6):12*10^(-6); %Radius of wire with organic layer

    MassWire_Organiclayer=10^(-6);%Mass of wire with organic layer

    MassWire=0.99*MassWire_Organiclayer;%Mass of wire

    MassOrganiclayer=0.01*MassWire_Organiclayer;%Mass organic layer

    Volume=MassWire_Organiclayer/DensitetWire_Organiclayer%Volume of wire with organic layer

    LengthWire_Organiclayer=Volume/(pi*RadiusWire_Organiclayer^2);% Length of wire with organic layer

    VolumeWire=MassWire/2620 %Volume wire

    VolumeOrganiclayer=MassOrganiclayer/800 %Volume organic layer

    RadiusWire=(VolumeWire/(pi*LengthWire_Organiclayer))^(1/2) %Radius wire


    RadiusOrganiclayer=RadiusWire_Organiclayer-RadiusWire % Radius organic layer

    Best Regards

    Robin
     
  2. jcsd
  3. Sep 6, 2010 #2

    Delphi51

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    Homework Helper

    For the wire, m = density*volume = dπr²h (1)
    For the coating, m = DV = D(πR²h - πr²h) = πhD(R²-r²) (2)
    where r and d are the radius and density of the wire,
    R and D the radius and density of the coating.
    You can get the value for h from equation (1).
    Then (2) can be used to find (R²-r²) and the thickness R-r. It worked out to about 40 x 10^-6 meters for me, but my calcs are not always correct!
     
  4. Sep 7, 2010 #3
    Dear Delphi51

    Thanks for your reply. I made mistake when I described my problem. 8.5*10^(-6)m is the radius of the wire with the organic layer. Sorry

    This means I have to find another method. Then I tried the code under. Do you have another method?

    DensitetWire_Organiclayer=800*0.01+2620*0.99; %Density of wire with organic layer

    RadiusWire_Organiclayer=8.5*10^(-6); %Radius of wire with organic layer

    MassWire_Organiclayer=10^(-6);%Mass of wire with organic layer

    MassWire=0.99*MassWire_Organiclayer;%Mass of wire

    MassOrganiclayer=0.01*MassWire_Organiclayer;%Mass organic layer

    Volume=MassWire_Organiclayer/DensitetWire_Organiclayer%Volume of wire with organic layer

    LengthWire_Organiclayer=Volume/(pi*RadiusWire_Organiclayer^2);% Length of wire with organic layer

    VolumeWire=MassWire/2620 %Volume wire

    VolumeOrganiclayer=MassOrganiclayer/800 %Volume organic layer

    RadiusWire=(VolumeWire/(pi*LengthWire_Organiclayer))^(1/2) %Radius wire


    RadiusOrganiclayer=RadiusWire_Organiclayer-RadiusWire % Radius organic layer

    Best Regards

    Robin
     
  5. Sep 7, 2010 #4

    Delphi51

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    Homework Helper

    I'm an old retired physics teacher and my memory doesn't persist long enough to follow your solution! The numbers are just a blur. I really need something more compact that I can see all at once.

    What happens if you take the ratio of the two equations I wrote earlier? The ratio of the masses is .01, the height cancels out and I think you are left with a relationship between the two radii. You know one of them, so you can use it to find the other.
     
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