Calculate Total Collisions of Free Electrons in Extension Cord

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SUMMARY

The discussion focuses on calculating the total number of collisions (N_c) of free electrons in a copper extension cord with a current of 8.0 A, length of 3.00 m, and diameter of 1.5 mm. The resistivity of copper is 1.7 x 10-8 Ω·m, and the concentration of free electrons is 8.5 x 1028 m-3. The drift velocity is given as 3.3 x 10-4 m/s. Participants express difficulty in determining the electric field necessary to calculate the acceleration of electrons, which is essential for finding the time between collisions (τ).

PREREQUISITES
  • Copper resistivity (1.7 x 10-8 Ω·m)
  • Drift velocity calculation (3.3 x 10-4 m/s)
  • Understanding of electron charge (1.6 x 10-19 C)
  • Concept of free electron concentration (8.5 x 1028 m-3)
NEXT STEPS
  • Calculate the electric field (E) in the extension cord using Ohm's law.
  • Determine the acceleration (a) of electrons using the formula a = eE/M_e.
  • Find the time between collisions (τ) using the relationship V_d = aτ.
  • Calculate the total number of collisions (N_c) using N_c = n * V_d * τ.
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Students and professionals in electrical engineering, physics enthusiasts, and anyone interested in understanding electron behavior in conductive materials.

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A current of I=8.0\;\rm A is flowing in a typical extension cord of length L=3.00 m. The cord is made of copper wire with diameter d=1.5mm.

The charge of the electron is e=1.6 *10^{-19} C. The resistivity of copper is \rho=1.7 *10^{-8}\; Omega*m. The concentration of free electrons in copper is n=8.5 *10^{28}\;m^{-3}.

Find the total number of collisions ( N_c) that all free electrons in this extension cord undergo in one second.

I know Velocity(drift) = 3.3 * 10^-4 m/s.

I tried to relate the formula V_d = a*Tau, to find Tau the time between collisions...

However given the information I was stuck solving for a = eE/M_e, because I could not determine the electric field...

Can someone please assist me on what information I might be missing?
 
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anyone?
 
im still stuck on this question...
 
ok so since no one seems to have a clue about this problem...

any suggestions of where I may be able to find the answer?
 

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