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A current of I=8.0\;\rm A is flowing in a typical extension cord of length L=3.00 m. The cord is made of copper wire with diameter d=1.5mm.
The charge of the electron is e=1.6 *10^{-19} C. The resistivity of copper is \rho=1.7 *10^{-8}\; Omega*m. The concentration of free electrons in copper is n=8.5 *10^{28}\;m^{-3}.
Find the total number of collisions ( N_c) that all free electrons in this extension cord undergo in one second.
I know Velocity(drift) = 3.3 * 10^-4 m/s.
I tried to relate the formula V_d = a*Tau, to find Tau the time between collisions...
However given the information I was stuck solving for a = eE/M_e, because I could not determine the electric field...
Can someone please assist me on what information I might be missing?
The charge of the electron is e=1.6 *10^{-19} C. The resistivity of copper is \rho=1.7 *10^{-8}\; Omega*m. The concentration of free electrons in copper is n=8.5 *10^{28}\;m^{-3}.
Find the total number of collisions ( N_c) that all free electrons in this extension cord undergo in one second.
I know Velocity(drift) = 3.3 * 10^-4 m/s.
I tried to relate the formula V_d = a*Tau, to find Tau the time between collisions...
However given the information I was stuck solving for a = eE/M_e, because I could not determine the electric field...
Can someone please assist me on what information I might be missing?