- #1
mcastillo356
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- Homework Statement
- A single charge of ##23\;\mu{C}## is at the origin of a ##x-y## coordinate system. Calculate the electric field vector at the point ##r=(1,25\;m,0,75\;m)##
- Relevant Equations
- ##\vec{E}=K\dfrac{q}{r^2}##
Really don't know if this is wright. Here it goes. Thanks in advance:
##\vec{E}=K\cdot{q}\cdot{\sqrt{\dfrac{1}{r_1^4}+\dfrac{1}{r_2^4}}}\cdot{\left(\dfrac{r_1}{\sqrt{r_1^2+r_2^2}}\hat{i}+\dfrac{r_2}{\sqrt{r_1^2+r_2^2}}\hat{j}\right)}##
##8,98\cdot{10^{9}}\;Nm^2/C^2\cdot{23,6\cdot{10^{-6}}\;C}\cdot{\left(\sqrt{\frac{1}{2,44\;m^4}+\frac{1}{3,16\;m^4}}\right)}\left(\dfrac{1,25\;m}{1,46\;m}\hat{i}+\dfrac{0,75\;m}{1,46\;m}\hat{j}\right)##
##8,98\cdot{10^{9}}\;Nm^2/C^2\cdot{23,6\cdot{10^{-6}}\;C}\cdot{0,852\;m^{-2}}\left(0,856\hat{i}+0,514\hat{j}\right)##
##\therefore \vec{E}=1,55\cdot{10^5}\;N/C\hat{i}+0,928\cdot{10^5}\;N/C\hat{j}##
My doubt: how is it such a large number?
Greetings!
##\vec{E}=K\cdot{q}\cdot{\sqrt{\dfrac{1}{r_1^4}+\dfrac{1}{r_2^4}}}\cdot{\left(\dfrac{r_1}{\sqrt{r_1^2+r_2^2}}\hat{i}+\dfrac{r_2}{\sqrt{r_1^2+r_2^2}}\hat{j}\right)}##
##8,98\cdot{10^{9}}\;Nm^2/C^2\cdot{23,6\cdot{10^{-6}}\;C}\cdot{\left(\sqrt{\frac{1}{2,44\;m^4}+\frac{1}{3,16\;m^4}}\right)}\left(\dfrac{1,25\;m}{1,46\;m}\hat{i}+\dfrac{0,75\;m}{1,46\;m}\hat{j}\right)##
##8,98\cdot{10^{9}}\;Nm^2/C^2\cdot{23,6\cdot{10^{-6}}\;C}\cdot{0,852\;m^{-2}}\left(0,856\hat{i}+0,514\hat{j}\right)##
##\therefore \vec{E}=1,55\cdot{10^5}\;N/C\hat{i}+0,928\cdot{10^5}\;N/C\hat{j}##
My doubt: how is it such a large number?
Greetings!
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