Calculate velocity of an oobject falling trhough a medium

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To calculate the velocity of a falling object through a medium while considering buoyancy and viscous drag, start with Newton's second law: m(dv/dt) = Fnet = mg - Drag - Buoyant force. The forces acting on the object include gravity pulling it downward and both viscous drag and buoyancy acting upward. The correct approach involves summing these forces to derive acceleration, which can then be integrated to find velocity. The resulting equation for velocity incorporates time and initial velocity, and if drag is velocity-dependent, the object will eventually reach terminal velocity. This method effectively accounts for the dynamics of the falling object in a medium.
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How do I calculate for velocity of a falling object through any medium at any given time if I have to consider both buoyancy and viscous drag.


If I consider Newtons law , I assume that it would be something like

m(dv/dt)=Fnet =mg-Drag-Buoyant force


Am I supposed to get a dimensionless quantity while doing dimensional analysis for such a problem.Whats the name of that number.



Thanks
 
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Since you are looking for a velocity, you wouldn't end with a dimensionless number. It would need to be in meters/second (or whatever distance/time measure you are using).

To do problems like this, consider all the different forces and the directions they are acting in. Then, use the sum of the forces equals mass*acceleration to get acceleration, and from there you can derive velocity.

For your problem, gravity is the only force acting to pull the object downward. Both viscous drag and buoyancy are acting upward, against gravity. So, your equation is correct (assuming down as the positive direction).

ma = Fg - Fd - Fb

Fg = force of gravity = mg
Fd = viscous drag force
Fb = buoyant force

From that, solve for acceleration (a) and integrate to get an equation for velocity.

a = (Fg - Fd - Fb)/m
v = [(Fg - Fd - Fb)/m]*t + Vo

where t = time and Vo = initial velocity.

Hope that helps!
 
If the drag force Fd is velocity dependent (Stokes or turbulent drag), the falling velocity will reach a terminal velocity. See

http://en.wikipedia.org/wiki/Drag_(physics )

Bob S
 
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For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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