Calculate Work, Power, PE and KE for a 400W Motor

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SUMMARY

This discussion focuses on calculating work, power, potential energy (PE), and kinetic energy (KE) for a 400W motor operating at 240V over a duration of 200 seconds. Key formulas mentioned include Work done = Power x Time, Potential Energy = mgh, and KE = 1/2 MV². The user seeks assistance in determining the time required to lift a 15kg mass vertically 5 meters and the velocity of the mass after falling 3.5 meters. The total energy conservation principle is also highlighted, indicating that KE and PE are inversely related.

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  • Understanding of basic physics concepts such as work, power, and energy
  • Familiarity with formulas for calculating potential energy (PE) and kinetic energy (KE)
  • Knowledge of basic algebra for rearranging equations
  • Experience with electric motor specifications and calculations
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  • Research the formula for calculating time taken to lift a mass using a motor
  • Learn about the conservation of energy principle in mechanical systems
  • Study the kinematic equations for motion under gravity
  • Explore practical applications of electric motors in lifting systems
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Students in physics, engineers working with mechanical systems, and anyone interested in understanding the dynamics of electric motors and energy calculations.

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I have a question where I am given watts, voltage and time. Let's say the electric motor is 400 watt that is run from 240v mains electricity for 200seconds.

I have managed to calculate the work done using the formula Work done (J) = Power (W) x time taken (J) And I have managed to calculate the current the motor uses using the formula Power = IV.

I have no idea how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.

I am also asked to calculate the PE of the fully raised mass, I assume here I would use this formula;

Potential= mgh (Am I right?)

How do I calculate it's velocity after falling for 3.5 metres? Do I use this formula? KE= 1/2 MV^2

Thanks.
 
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The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.
 
edgepflow said:
The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.

I figured how to work out but the others.
 
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2
 
The total Energy is constant: KE + PE = constant. If one goes down, the other goes up.
 
Naty1 said:
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2

But if I rearrange the formula (making v0 the subject) it will only give me the original velocity and not the velocity is is at after 3.5 metres. Are saying that after finding this I should use; v^2 = u^2 + 2as to find the velocity at 3.5 metres?

how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.
 
Hi, Could someone please help me out.
 

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