Calculate Work, Power, PE and KE for a 400W Motor

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Homework Help Overview

The discussion revolves around calculating work, power, potential energy (PE), and kinetic energy (KE) in the context of a 400W electric motor operating a pulley system. The original poster presents a scenario involving a motor connected to a pulley that raises a 15kg mass vertically.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate work done and current using given formulas but expresses uncertainty about determining the time to raise a mass and calculating its velocity after falling. Other participants reiterate the relationships between energy, power, and potential energy, while some explore the kinematic equations for velocity.

Discussion Status

Participants are actively engaging with the problem, exploring various equations and concepts related to energy conservation and motion. There is a mix of attempts to clarify the relationships between different forms of energy and how to apply kinematic equations, but no consensus has been reached on the specific calculations needed.

Contextual Notes

Participants are working within the constraints of the problem as presented, including the specific values for power, mass, and height, while also questioning the assumptions behind the calculations and the application of formulas.

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I have a question where I am given watts, voltage and time. Let's say the electric motor is 400 watt that is run from 240v mains electricity for 200seconds.

I have managed to calculate the work done using the formula Work done (J) = Power (W) x time taken (J) And I have managed to calculate the current the motor uses using the formula Power = IV.

I have no idea how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.

I am also asked to calculate the PE of the fully raised mass, I assume here I would use this formula;

Potential= mgh (Am I right?)

How do I calculate it's velocity after falling for 3.5 metres? Do I use this formula? KE= 1/2 MV^2

Thanks.
 
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The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.
 
edgepflow said:
The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.

I figured how to work out but the others.
 
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2
 
The total Energy is constant: KE + PE = constant. If one goes down, the other goes up.
 
Naty1 said:
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2

But if I rearrange the formula (making v0 the subject) it will only give me the original velocity and not the velocity is is at after 3.5 metres. Are saying that after finding this I should use; v^2 = u^2 + 2as to find the velocity at 3.5 metres?

how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.
 
Hi, Could someone please help me out.
 

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