Calculating Acceleration and Tension in a Pulley System on an Inclined Plane

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Homework Help Overview

The problem involves a mass on a frictionless incline connected to a pulley, with specific parameters given such as the incline angle, mass, moment of inertia of the pulley, and radius. The original poster seeks to calculate the acceleration of the mass, the angular acceleration of the pulley, and the tension in the string.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive equations for acceleration and tension using free body diagrams and rotational dynamics. Some participants question the arithmetic and the specific values used, such as the gravitational constant and significant figures.

Discussion Status

Participants have provided some agreement on the formulas used by the original poster, but there is uncertainty regarding the correctness of the answers. The original poster expresses concern about their answers being marked wrong, prompting further inquiry into the details of the problem setup.

Contextual Notes

There is mention of potential issues with significant figures and the specific value of gravitational acceleration to use. The original poster indicates they are uncertain about which parts of their work are correct or incorrect.

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A mass is placed on a frictionless incline and attached to a pulley by a light string. The situation is sketched below.



The incline angle, theta, is 42.0°, the mass is 3.00 kg, the moment of inertia of the pulley is 0.400 kgm2 and the radius of the pulley is 0.145 m. The mass is released from rest.

(a) What is the magnitude of the acceleration of the mass?
___________m/s2
(b) What is the magnitude of the angular acceleration of the pulley?
___________rad/s2
(c) What is the tension in the string?
___________ N


Attempt
T =tension in the string which opposes mass
weight perpendicular to ramp = mgsinθ
a= linear acceleration
mgsinθ-T=ma

Iα=T*r(Because force on pulley is tension T and distance from center of pulley is r)

α=a/r

T=Iα/r=Ia/r2

substituting in
mgsinθ-Ia/r2=ma
mgsinθ=a(m+I/r2)
a=mgsinθ/(m+I/r2)=0.8931m/s2

b)α=0.9/0.145=6.1599rad/s2
c)T=Ia/r2=0.4*0.9/(0.145)2=17N

can someone who knows what they are doing look this over and fix any mistakes.
Please i really need this.
 

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That seems ok to me.
 
Welcome to PF!

Hi squintyeyes! Welcome to PF! :wink:

(I haven't checked your arithmetic :redface:, but apart from that I agree with Dick) your formulas are fine. :smile:
 
but my answers are marked wrong and i am down to my last try
 
(just got up :zzz: …)
squintyeyes said:
but my answers are marked wrong and i am down to my last try

hmm … it would have helped if you'd said that at the start. :redface:

well, I've looked at it again, including the arithmetic, and I can't see what's wrong.

Which parts are marked right, and which wrong?

How many sig figs are you supposed to enter? how many did you enter?

Are you supposed to use g = 9.8 or 9.81?

Are you sure it says "radius", not "diameter"?
 
Thanks for looking at this. I plugged the first two answers to three decimal places and got them both wrong and it says radius not diameter. I am lost. Thanks again
 

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